(21x-2)^2=(38x+5)

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Solution for (21x-2)^2=(38x+5) equation: 



(21x-2)^2=(38x+5)

We move all terms to the left:

(21x-2)^2-((38x+5))=0



We calculate terms in parentheses: -((38x+5)), so:

(38x+5)

We get rid of parentheses

38x+5

Back to the equation:

-(38x+5)



We get rid of parentheses

(21x-2)^2-38x-5=0

We add all the numbers together, and all the variables

-38x+(21x-2)^2-5=0

We move all terms containing x to the left, all other terms to the right

-38x+(21x-2)^2=5

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